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Stationary waves are setup in an air column. Velocity of sound in air is `330 ms^(-1)` and frequency is `165 Hz`. The distance between two successive nodes is
A. 2m
B. 1m
C. 0.5m
D. 4m

1 Answer

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by (84.9k points)
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Best answer
Correct Answer - B
The distance between antinode to antinode is
`=lamda /2 = 2/2 = 1m.`

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