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A stretched sonometer wire is in unison with a tuning fork. When the length of the wire is decreased by 1% 6 beats/s are heard, then the frequency of the tuning fork is
A. 594 Hz
B. 606 Hz
C. 600 Hz
D. 612 Hz

1 Answer

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Best answer
Correct Answer - A
`l_2=l_1-(l_1)/(100)= l_1 (1-0.01)=0.99l_1`
`n_2-n_1 = 6`
`n_1/n_2 = l_2/l_1 therefore n_1 = l_2/l_1 n_2 = 0.99 n_2`
`n_2 - 0.99n_2 =6`
`0.01n_2=6 therefore n_2 = 600Hz.`
`n_1=n_2-6=600-6=594Hz`

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