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The freezing point of benzene decreases by 2.122 K when 2.5 g of benzoic acid (C6H5COOH) is dissolved

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The freezing point of benzene decreases by 2.122 K when 2.5 g of benzoic acid (C6H5COOH) is dissolved in 25 g of benzene. If benzoic acid forms a dimer in benzene, calculate the van't Hoff factor and the percentage association of benzoic acid. (Kf for benzene = 5.12 K kg mol-1)

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α = 0.99

Percentage association of benzoic acid is 99.0%

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