Correct option is (B) 1 : √3 : 2
Let \(\angle A=30^\circ,\angle B=90^\circ\;\&\;\angle C=60^\circ\) in \(\triangle ABC.\) also BC = 1 unit.
Then tan A \(=\frac{BC}{AB}\)
\(\Rightarrow\) \(AB=\frac{BC}{tan\,30^\circ}\) \((\because\angle A=30^\circ)\)
\(=\frac1{\frac1{\sqrt3}}\) \(=\sqrt3\) unit
And sin A \(=\frac{BC}{AC}\)
\(\therefore\) \(AC=\frac{BC}{sin\,30^\circ}\)
\(=\frac1{\frac12}=2\)
\(\therefore BC:AB:AC=1:\sqrt3:2\)
Hence, the ratio of its sides is \(1 : \sqrt 3 : 2.\)
