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+1 vote
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in Physics by (84.9k points)
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A stationary wave incident on rigid wall. Then the distance between wall and first antinode is (velocity of wave is 36 m/s and frequency 72Hz)
A. 1/2m
B. 1/4m
C. 1/8m
D. 1m

1 Answer

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by (86.7k points)
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Best answer
Correct Answer - C
`lamda = v/n`
`lamda/4 = (v)/(4n)`
`=(36)/(4xx72)`
`lamda/4 = 1/8 m`

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