Question

If the density of the gas at NTP is 0.178 `km//m^(3)`, then the R.M.S. velocity of the molecules of a gas at N.T.P. will be `(P_(0)=10^(5)N//m^(2))`
A. 1306 m/s
B. 13.06 km/s
C. 130.6 km/s
D. 1340 m/s

Answer 1

Correct Answer - A
`C_(rms)=sqrt((3P)/(rho))=sqrt((3xx10^(5))/(0.178))=sqrt((3xx108)/(178))`
=1308 m/s.