Question

The temperature at which the r.m.s. velocity of oxygen molecules equal that of nitrogen molecules at `100^(@)C` is nearly.
A. 42.63 K
B. 426.3 K
C. 4263 K
D. 4.263 K

Answer 1

Correct Answer - B
`V_(n)=V_(o)`
`sqrt((3RT_(n))/(M_(n)))=sqrt((3RT_(o))/(M_(o)))`
`(T_(o))/(T_(n))=(M_(o))/(M_(n))`
`T_(o)=373xx(32)/(28)=426.3K`