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निम्न चित्र में ` 1 Omega ` प्रतिरोध में धारा होगी -
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माना Q से P के मध्य x दुरी तथा ` Omega ` के परितः विभवांतर
` (x-6)/3 + (x-0)/1 + (x+9)/5 = 0 `
या ` x/3 - 2 + x/1 + x/5 + 9/5 = 0`
या `(5x+15x+3x)/(15) + (9-10)/5 = 0 `
या` (23x)/15 = 1/5 ` या ` x = 3/23`
` :. I = (x-0)/1 3/23 = 0.13 A ` ( Q से P की ओर)

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