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+1 vote
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in Physics by (84.9k points)
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A carnot engine takes 300 cal. of heat at 500 k and rejects 150 cal of heat to the sink. The temperature (in k) of sink is __________.
A. 1000 K
B. 750 K
C. 250 K
D. 125 K

1 Answer

+1 vote
by (86.7k points)
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Best answer
Correct Answer - C
`eta=(W)/(Q)=1-(T_(2))/(T_(1))`
`therefore (T_(2))/(T_(1))=(Q-W)/(Q)`
`T_(2)=500(150)/(300)=250K`.

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