(i ) श्रेणीक्रम मैं-
` " "R= R_1 + R_2 +R_3`
` " "=3+ 6+8 =17 Omega `
(ii ) समांतर क्रम में-
` " "(1)/(R) =(1)/(R_1) +(1)/(R_2)+ (1)/(R_3)" = (1)/(3) + (1)/(6) +(1)/(8) `
` " "= ( 8+ 4+3)/( 24) `
` " " = (15)/( 24) `
` therefore " "R =( 24)/( 15) =(8)/( 5)`
` " " 1.6Omega`