Question

In a biprism experiment, the wavelenght of monochromatic light is `6000Å`. The distance between two virtual images is 6 mm . The number of fringes formed per mm on a screen placed at a distance of 1 m is
A. 5
B. 10
C. 15
D. 20

Answer 1

Correct Answer - B
`beta=(D)/(d) lambda =(1xx6xx10^(-7))/(6xx10^(-3))=0.1 mm`
Thus,
No. of fringes formedper mm of screen `=(1)/(0.1)=10`