Correct Answer - C
Suppose that the man jumps with the same initial velocity (u) on both the planets.
`because u^(2)=2gh " " therefore h=(u^(2))/(2g)`
`therefore (h_(A))/(h_(B))=(u^(2))/(2g_(A))xx(2g_(B))/(u^(2))=(g_(B))/(g_(A))`
But `h_(A)=2.5 m` and `g_(A)=8g_(B)`
`therefore h_(B)=8xx1.5=20 m`