Question

The cell in which the following reaction occurs :

2Fe³⁺(aq) + 2I^-(aq) → 2Fe²⁺(aq) + I₂(s) has E°_cell = 0.236 V at 298K. Calculate the standard Gibb's energy and the equilibrium constant of the cell reaction.

(Antilog of 6.5 = 3.162 x 10⁶; of 8.0 = 10 x 10⁸; of 8.5 = 3.162 x 10⁸)

Answer 1

△_rG° = -nFE°_cell

= -2 x 96500 x 0.236

= 45.548 kJ/mol