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The escape velocity of a body on the surface of the earth is `V_(e)`. What is the escape velocity on a planet whose radius is thrice the radius of the earth and whose mass is double the mass of the earth?
A. `sqrt((3)/(2))V_(e)`
B. `sqrt((2)/(3))Ve`
C. `(2)/(3)V_(e)`
D. `(sqrt(3))/(2)V_(e)`

1 Answer

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Best answer
Correct Answer - B
`V_(e)=sqrt((2GM)/(R ))" " therefore V_(e)prop sqrt((M)/(R ))`
`therefore (V_(P))/(V_(e))=sqrt((M_(P))/(R_(P))xx(R_(E ))/(M_(E )))=sqrt((2)/(3))" " therefore V_(P)=sqrt((2)/(3))V_(e)`

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