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An ideal spring with spring constant k is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the spring is
A. `(4Mg)/(K)`
B. `(2Mg)/(K)`
C. `(Mg)/(K)`
D. `(Mg)/(2K)`

1 Answer

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Best answer
Correct Answer - B
Let x be the maximum extension of the spring. When it is loaded with a mass M and released. There is a decrease in the gravitational P.E. and it is = Mgx
But this increases P.E. of the spring
`therefore P.E. =(1)/(2)Kx^(2) " " therefore (1)/(2)Kx^(2)=Mgx " " therefore x = (2Mg)/(K)`

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