Correct Answer - C
In figure, `3Omega` and `3 Omega` are in series which is equal to `6Omega` . Now `6 Omega ` and `6 Omega` are in parallel and their equivalent is `3Omega`. Thus finally `3Omega` and `3Omega` are in parallel.
`:.R_(P)=(6xx3)/(6+3)=(18)/(9)=2Omega`.
