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A potentiometer wire is 500 cm long and potential difference of 4 V is maintained between the ends of the wire. The e.m.f. of the cell which balances against the length of 135 cm of the wire is
A. 0.08 V
B. 2.08 V
C. 2.88V
D. 1.08 V

1 Answer

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Best answer
Correct Answer - D
`(E_(1))/(V)=(I rho l_(1))/(I rho l) " " :.E_(1)=(4xx1.35)/(5)=1.08V`

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