Question

The magnetic flux linked with a coil is given by `phi=5t^(2)+3t+2`
What is the e.m.f. Induced in the coil in the third second?
A. 5 V
B. 10 V
C. 15 V
D. 20 V

Answer 1

Correct Answer - B
`e = (d phi)/(dt) = d/(dt)(5t^(2)+3t+2)=10t+3`
When `t=2 sec, e_(1)=20+3=23 V`
When `t=3 sec, e_(2)=30+3=33`
`:.` e.m.f. induced in the third second = 33 - 23 = 10V.