Question

A voltmeter of resistance `2000 Omega` reads 1 volt/division. The resistance required to be connected in series with voltmeter to make it to read 10 volt/divistion is
A. `18 Omega`
B. `180 Omega`
C. `1800 Omega`
D. `18000 Omega`

Answer 1

Correct Answer - D
Let x be the total number of divisions on voltmeter. Thus , `V_g=x and V =10 x`.
Now , `V_g=I_g G therefore I_g=V_g//G=x//2000`
Thus , `R=(V)/(I_g)-G=(10x)/((x//2000))-2000`
`=18000Omega`