Question

The phase difference between the voltage and the current in an AC circuit is `pi//4`. If the frequency is `50Hz` then this phase difference will be equivalent to a time of
A. 0.05 s
B. 2.5 millisecond
C. 25 millisecond
D. 0.25 s

Answer 1

Correct Answer - B
Phase diff. = `(pi)/4 T = 1/n = 1/50 s`
`:.` Time T correspond to a phase diff. of `2 pi`
`:.` for a phase diff. of `(pi)/4`.
`t = T/8 = 1/(50 xx 8) = 1/400 s :. t= 2.5` millisecond.