Question

When a battery of emf 2 V is directly connected to a galvanometer of resistance `100 Omega`. It shows full scale deflection. To measure 1 A current , the shunt must be
A. `(49)/(10)Omega`
B. `(10)/(49)Omega`
C. `(100)/(49)Omega`
D. `(49)/(100)Omega`

Answer 1

Correct Answer - C

For same current , Initial resistance = Final resistance of circuit
i.e., `G=(G.S)/(G+S)+R therefore R=(G^2)/(G+S)`.