Question

An alternating e.m.f. `E=10sqrt(2) sin omega` volt is applied to a circuit containing a pure inductance L and a resistance and voltage acros the resistance is 6 v between the current and potential difference in this circuit is
A. 10 V
B. 8 V
C. 6 V
D. 12 V

Answer 1

Correct Answer - B
`V_(rms) = (10sqrt(2))/(sqrt(2)) = 10 V`
`:. 10^(2) = sqrt(V_(L)^(2)+V_(R)^(2)) :. 100 = 36 + V_(L)^(2) :. V_(L) = 8V`.