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The combined resistance of a galvanometer of resistance of `495` ohm and its shunt is `9.9 Omega` . The shunt resistance is
A. `1.01Omega`
B. `8.9Omega`
C. `10.1Omega`
D. `9.1Omega`

1 Answer

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Best answer
Correct Answer - C
`R_A =(GS)/(S+G)`
`9.9 S +495xx9.9 = 495 S S =(495xx9.9)/(485.1)=10.1Omega `.

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