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Two coils are made of same material such that radius of one coil is twice of the other and magnetic field is same at the centres then ratio of potential difference applied across `1^st` to second coil is
A. 2 times
B. same
C. 4 times
D. 3 times

1 Answer

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Best answer
Correct Answer - C
For same length
`B=(mu_0 n I)/(2a)`
`I=(B2a)/(mu_0n)` i.e.,`1prop (1)/(a^2)` for same length.
`therefore (I_2)/(I_1)=((a_1)/(a_2))^2`
`(I_2)/(I_1)=((2a_2)/(a_2))^2`
`I_2=4I_1(because Vprop I)`
i.e., `V_2=4V_1`.

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