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A coil having an inductance of 50 mH and a resistance of `10 Omega` is connected in series with a `25 muF` capacitor across a 200 V supply. What is the Q factor of the circuit at resonance?
A. 3.5
B. 4.47
C. 5.5
D. 7

1 Answer

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Best answer
Correct Answer - B
Q factor =`1/R sqrt(L/C) = 1/10sqrt((50xx10^(-3))/(25 xx 10^(-6)))`
`1/10sqrt(2000) = sqrt(20) = 4.47`.

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