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The areas of cross-section of three magnets of same length are A,2AA and 6A respectively The ratio of their magnetic moments will be
A. `6:2:1`
B. `1:2:6`
C. `1:4:36`
D. `36:4:1`

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Best answer
Correct Answer - B
M`oo`A
`therefore M_(1):M_(2)M_(3)=A_(1):A_(2):A_(3)`
`=A:2A:6A`
=`1:2:6`

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