Question

An electron in an atom revolves the nucleus in an orbit of radius 0.53 Å equivalent magnetic moment,if the frequency of revolution of electron is `6.8xx10^(9)` MHz is
A. `9.603xx10^(-24) Am^(2)`
B. `6.603xx10^(-24) Am^(2)`
C. `3.603xx10^(-24)Am^(2)`
D. `2.603xx10^(-24)Am^(2)`

Answer 1

Correct Answer - A
Period T=`(1)/(f)=(1)/(6.8xx10^(15))`
current I=`(e)/(T)`=ef
The electron revolving in the circular orbit behaves as a current loop and hence possesseve magnetic moment.
M=`IA=efxxpir^(2)`
`therefore M=1.6xx10^(-19)xx6.8xx10^(15)xx3.142xx(0.53xx10^(10))^(2)`
`therefore M=9.603xx10^(-24)Am^(2)`