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Calculate the time to deposit 1.27 g of copper at cathode when a current of 2 A was passed through the solution of CuSO4.

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Calculate the time to deposit 1.27 g of copper at cathode when a current of 2 A was passed through the solution of CuSO4.

(Molar mass of Cu = 63.5 g mol-1, 1 F = 96500 C mol-1 )

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1 Answer

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Best answer

Cu2+ + 2e- → Cu

OR

By Faraday's first law

m = z x i x t

z = atomic mass/valency x F

1.27 = 63.5 X 2 X t/2 x 96500

t = 1930 s 

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