Question

An a.c. voltage of peak value 20 V is connected in series with a silicon diode and a load resistance of 500 G. The forward resistance of the diode is 10 G and the barrier voltage is 0.7 V. Find the peak current through diode and the peak voltage across the load.
A. 37.8 mA, 18.9 V
B. 5 mA, 30 V
C. 30 mA, 5 V
D. 2 mA, 2 V

Answer 1

Correct Answer - A
`I_(0)=(e_(0)-V+_(b))/(R+r_(f))=(20-0.7)/(500+10)=37.8 mA`
Now, `V_(0) =I_(0)*R_(l)`
`=37.8xx10^(-3)xx500`
`=18.9`V .