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For a particle performing linear SHM, its average speed over one oscillation is (where, a= amplitude of SHM, n=frequency of oscillation)
A. 2 an
B. 4 an
C. 6 an
D. 8 an

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Correct Answer - B
Distance tavelled in one oscillation is 4a, time periods, T,
Velocity = Distance/Time
Velocity `=(4a)/(T )= 4 an`

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