N2 + 3H2 → 2NH3
The rate of reaction can be represented as:
Rate = \(\frac{-d[N_2]}{dt} = - \frac 13 \frac{d[H_2]}{dt} = + \frac 12 \frac{d[NH_3]}{dt}\)
\(\frac{-d[N_2]}{dt} = -\frac 12 (2\times 10^{-2})\)
\(\frac{-d[N_2]}{dt} = 10^{-2} \) mol / dm3 / s