Question

Consider the following relations for `emf` of a electrochemical cell
(i) emf of cell = (Oxidation potential of anode)-(Reduction potential of cathode)
(ii) emf of cell = (Oxidation potential of anode)+(Reduction potential of cathode)
(iii) emf of cell = (Reduction potential of anode)+(Reduction potential of cathode)
(iv) emf of cell = (Oxidation potential of anode)-(Oxidation potential of cathode)
Which of the above realtions are correct?
A. (iii) and (iv)
B. (i) and (ii)
C. (iii) and (iv)
D. (ii) and (iv)

Answer 1

Correct Answer - D
EMF of a cell = Reduction potential of cathode - Reduction potential of anode = Reduction potential of cathode + Oxidation of anode = Oxidation potential of anode - Oxidation potential of cathode