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`C_(3) H_(8)+Br_(2) overset(AlBr_(3)) to A` (major product)
`C_(2)H_(5)ONa+A to B`.
What is B in above reaction ?
A. `CH_(3)CH_(2)CH_(2)OC_(2)H_(5)`
B. `CH_(3) CH=CH_(2)`
C. `(CH_(3))_(2)CHOC_(2)H_(5)`
D. all of the above

1 Answer

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Best answer
Correct Answer - B
`CH_(3)H_(8)+Br to CH_(3)-CHBr-CH_(3)`
`C_(2)H_(5)Ona+CH_(3)-CHBrCH_(3) to CH_(3)CH=CH_(2)`

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