Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
159 views
in Physics by (90.7k points)
closed by
The magnetic moment of a short bar magnet placed with its magnetic axis at `30^(@)` to an external field of 900 G and experiences a torque of 0.02 N m is
A. `0.35Am^(2)`
B. `0.44Am^(2)`
C. `2.45Am^(2)`
D. `1.5Am^(2)`

1 Answer

0 votes
by (91.8k points)
selected by
 
Best answer
Correct Answer - B
Here, B=900, Gauss=`900xx10^(-4)T`
`=9xx10^(2)T`
`tau=0.02Nm and theta=30^(@)`
`Rightarrow 0.02=9xx10^(-2)xx(1)/(2)xxm`
`m=(0.02xx2)/(9xx10^(-2))=0.44Am^(2)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...