Question

10 moles of a mixture of hydrogen and oxygen gases at a pressure of 1 atm at a constant volume and temperature, react to form 3.6 g of liquid pressure of the resulting mixture will be closest to :
A. 1.07 atm
B. 0.97 atm
C. 1.02 atm
D. 0.92 atm

Answer 1

Correct Answer - B
`2H_(2)+O_(2)to 2H_(2)O`
Initially x mol (10-x)mol 0
After reaction x-a `(10-x-a/2)` a
As per reaction ,
`a=3.6/18 =0.2`
`:.` Resulting mole of gases in the mixture `=x-0.2+10-x0.2/2=10-0.3=9.7`
`:.` from relation
`(P_(1))/(n_(1))=(P_(2))/(n_(2))`
`1/10=(P_(2))/9.7`
`P_(2)=0.97 atm`.