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The number of electrons involved in the reduction of nitrate `(NO_(3)^(ө))` to hydrazine `(N_(2)H_(4))` is
A. 8
B. 7
C. 5
D. 3

1 Answer

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Best answer
Correct Answer - B
`overset(+5)(NO_(3)^(-))+n e^(-)rarr1//2H_(2)overset(-2)(N)-overset(-2)(NH_(2))`
`-n=-2`
`n=5+2=7`.

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