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The molar conductances of `NaCI, HCI` and `CH_3 COONa` at infinite dilution are `12.45, 426. 16` and ` 91 "ohm"^(-1) cm^2 "hol"^(-1)` respectively. The molar conductance of `CH_3COOH` at infinite dilution is .
A. 201.28 `ohm^(-1)cm^(2)`
B. `390.71 ohm cm^(2)`
C. `698.28ohm cm^(2)`
D. `540.48ohm cm^(2)`

1 Answer

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Best answer
Correct Answer - B
`^^_(C_(2)H_(5)COOH)^(0)=^^_(C_(2)H_(5)COONa)^(0)+^^_(HCl)^(0)-^^_(NaCl)^(0)`
`=91+426.16-126.45`
`=390.71ohm^(-1)cm^(2)`.

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