Question

The standard `EMF` of a galvanic cell involving cell reaction with `n=2` is found to be `0.295 V` at `25^(@)C` . The equilibrium constant of the reaction would be
A. `1.0xx10^(10)`
B. `2.0xx10^(11)`
C. `4.0xx10^(12)`
D. `1.0xx10^(2)`

Answer 1

Correct Answer - A
`E^(@)=(0.0591)/(n)"log" k_(c)`
`0.295=(0.0591)/(2)"log"k_(c)`
`"log" k_(c)=(0.295xx2)/(0.0591)`
`"log" k_(c)=9.9830`
`k_(c)="antilog" 9.9830=10^(10)`