Question

The mutual inductance between two adjacent coils is 1.5 H. If the current in the primary coil changes from 0 to 20 A in 0.05 s, determine the average emf induced in the secondary coil. If the number of turns in the secondary coil is 800, what change in flux will be observed in it?

Answer 1

The average value of induced emf,
`e=-M(DeltaI)/(Deltat)=-1.5xx((20-0))/(0.05)=-(1.5xx20)/(0.05)=-600V`
Hence, the magnitude of the induced emf = 600 V.
Again, from the relation `phi=MI` we get,
change in flux, `Deltaphi=M.DeltaI=1.5xx(20-0)=30Wb`.