Question

A current flowing through a coil changes from +2A to -2A in 0.05 s and an emf of 8 V is induced in the coil. The value of self-inductance of the coil is
A. 0.8 H
B. 0.1 H
C. 0.2 H
D. 0.4 H

Answer 1

Correct Answer - B
We know, `e=-L(dI)/(dt)`
or, `L=(-edt)/(dI)=(8xx0.05)/(-2-(+2))=(0.4)/(4)=0.1H`