Question

The number of turns in the primary and secondary coils of an ideal transformer are 140 and 280, respectively. If the current through the primary coils is 4 A, what will be the current in the secondary coil?

Answer 1

In an ideal transformer, the powers of the secondary and primary coild are equal,
i.e., `V_sI_s=V_pI_p`
`therefore I_s=I_p.p/V_s=I_P.N_P/N_s=4times140/280=2A`.