Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
78 views
in Physics by (91.8k points)
closed by
In an ac circuit alternating voltage E=`200sqrt2` sin 100t volt is connected to a capacitor of capacity`1muF`. The rms value of the current in the circuit is
A. 10 mA
B. 100 mA
C. 200 mA
D. 20 mA

1 Answer

0 votes
by (90.7k points)
selected by
 
Best answer
Correct Answer - D
From the given equation, we may write
`E_0=200sqrt2V`and `omega=100rad//s`
`X_C=1/(omegaC)=1/(100times(1times10^-6))=10^4Omega`
`thereforeI_(rms)=E_(rms)/X_C=sqrt2/X_C=sqrt2/10^4=20 mA`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...