Question

`H_(2)O(l)toH_(2)O(g)` , `DeltaH=+43.7 kJ`
`H_(2)O(s)toH_(2)O(l)` , `DeltaH=+6.05kJ`
The value of `DeltaH_((sublimation))` of ice is
A. `49.75 kJ mol^(-1)`
B. `37.65 kJ mol^(-1)`
C. `43.7 kJ mol^(-1)`
D. none of these

Answer 1

Correct Answer - A
Add the two equations to get
`H_(2)O(s) to H_(2)O(g)`