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The heat change for the following reaction at `298 K` and constant pressure is `+7.3 kcal`
`A_(@)B(s)to2A(s)+(1)/(2)B_(2)(g)` ,` DeltaH=+7.3 kcal`
The heat change at constant volume would be
A. `+7.3kcal`
B. More than `7.3kcal`
C. Less than `7.3 kcal`
D. Zero

1 Answer

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Best answer
Correct Answer - C
`DeltaH=DeltaE+Deltan_(g)RT`
or `DeltaE=DeltaH-Deltan_(g)RT`
`:. DeltaE=+7.3-(1)/(2)xx2xx298`
`=7300 cal-298`
`=7002 cal=7.00 kcal`

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