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\(\cfrac{1}{log_{x}xy}\) + \(\cfrac{1}{log_{y}xy}\)

1/logx xy + 1/logy xy 

A) 0 

B) 1 

C) -1 

D) 2

2 Answers

+1 vote
by (57.0k points)
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Best answer

Correct option is (B) 1

\(\frac{1}{log_x\,xy} + \frac{1}{log_y\,xy} \) \(=\frac{1}{log_x\,x+log_x\,y} + \frac{1}{log_y\,x+log_y\,y} \)   \((\because\) log AB = log A + log B)

\(=\frac{1}{1+log_x\,y} + \frac{1}{1+log_y\,x} \)   \((\because log_aa=1)\)

\(=\frac{1}{1+log_x\,y} + \frac{1}{1+\frac1{log_x\,y}} \)    \((\because log_a\,b=\frac1{log_b\,a})\)

\(=\frac{1}{1+log_x\,y} + \frac{log_x\,y}{1+log_x\,y} \)

\(=\frac{1+log_x\,y}{1+log_x\,y}=1\)

+1 vote
by (37.5k points)

Correct option is B) 1

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