Correct option is (B) 1
\(\frac{1}{log_x\,xy} + \frac{1}{log_y\,xy} \) \(=\frac{1}{log_x\,x+log_x\,y} + \frac{1}{log_y\,x+log_y\,y} \) \((\because\) log AB = log A + log B)
\(=\frac{1}{1+log_x\,y} + \frac{1}{1+log_y\,x} \) \((\because log_aa=1)\)
\(=\frac{1}{1+log_x\,y} + \frac{1}{1+\frac1{log_x\,y}} \) \((\because log_a\,b=\frac1{log_b\,a})\)
\(=\frac{1}{1+log_x\,y} + \frac{log_x\,y}{1+log_x\,y} \)
\(=\frac{1+log_x\,y}{1+log_x\,y}=1\)