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iodine oxidises the `S_2O_3^(2-)` ion to

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iodine oxidises the `S_2O_3^(2-)` ion to
A. `SO_3^(2-)`
B. `SO_4^(2-)`
C. `S_4O_6^(2-)`
D. `S^(2-)`
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Correct Answer - C
`I_2+S_2O_3^(2-)tounderset("Tetrathionate ion")(S_4O_6^(2-)) +2I^(-)`
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