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`Mg+2HCl toMgCl_(2)+H_(2)`. The ration of Mg used to `H_(2)` produced by weight is

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`Mg+2HCl toMgCl_(2)+H_(2)`. The ration of Mg used to `H_(2)` produced by weight is
A. `1:12`
B. `12:1`
C. `24:1`
D. `1:6`
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Correct Answer - B
`underset(24g)(Mg)+2HCl to MgCl_(2)+underset(2g)(H_(2))`
Mass of Mg used: Mass of hydrogen produced
`= 24:2=12:1`
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