Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
77 views
in Chemistry by (83.4k points)
closed
Arrange the following ions in the order of decreasing `X-O` bond length where X is the central atom:
A. `ClO_4^(-),SO_4^(2-),PO_4^(3-),SiO_4^(4-)`
B. `SiO_4^(4-), PO_4^(3-), SO_4^(2-), ClO_4^(-)`
C. `SiO_4^(4-), PO_4^(3-), ClO_4^(-), SO_4^(2-)`
D. `SiO_4^(2-),SO_4^(2-),PO_4^(3-),ClO_4^(-)`

1 Answer

0 votes
by (91.0k points)
 
Best answer
Correct Answer - B
image
Greater the bond order, shorter is the bond length.
Hence X-O bond length will be in the order `SiO_4^(4-) gt PO_4^(3-) gt SO_4^(2-) gt ClO_4^(-)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...