Question

Which of the two lons from the list given have the geometry that is explained by the same hybridization of orbitals `NO_(2)^(-),NO_(3)^(-) ,NH_(2)^(-) NH_(4)^(+) SCN^(-)`?
A. `NO_2^-` and `NH_2^-`
B. `NO_2^-` and `NO_3^-`
C. `NH_4^+` and `NO_3^-`
D. `SCN^(-) and NH_2^-`

Answer 1

Correct Answer - B
number of hybrid orbitals X=`1/2` [VE+MA 2 - C+ a]
where VE = [no. of valence electrons of the central atom]
MA = [no of monovalent atoms/group surrounding the central atom]
C=[Charge on the cation if the given species is a poly atomic cation]
a=[ Charge on the anion if the given species is a polyatomic anion]
Note : Only monovalent atoms (MA) or group are to be considered. For divalent anions MA=0.
Value of X
`{:("Value of X",2,3,4,5,6,7),("Type of hybridization",sp,sp^2,sp^3,sp^3d,sp^3d^2,sp^3d^3):}`
Applying the formula,
X = `1/2`[VE + MA -C + a] find out the type of hybridization
`NO_2^(-) to sp^2 , NO_3^(-) to sp^2 , NH_2^(-)tosp^3`
`NH_4^(+)tosp^3, SCN^(-)tosp`.