Correct Answer - C
Because the compound reacts with `[Ag(NH_(3))_(2)]^(+)` it must have=CH group. Further as it gives `(CH_(3))_(3)C-COOH` with alkaline `KMnO_(4)` it should have `(CH_(3))_(3)C-C`= group. Therefore the compound is as shown in (C ) `(CH_(3))_(3)C--=CH overset(Alk.KMnO_(4))to (CH_(3))_(3)C-COOH+CO_(2)+H_(2)O`